[新しいコレクション] (1-x^2)y'' 2xy'=0 241723-(1-x^2)y''-2xy'+12y=0

Then it may be seen that xy' = dy/dt and (x^2)y'' = (d^2/dt^2)y (dy/dt) The equation becomes (D^2 2D 1)y = (1e^t)^(2), where the operator D denotes differentiation with respect to t The homogeneous equation corresponding to the above equation is (D^2 2D 1)y = 0,

(1-x^2)y''-2xy'+12y=0-Share It On Facebook Twitter Email 1 Answer 1 vote answered by Vikash Kumar (260k points) Best answer Given differential equation is Hence general solution is ← Prev QuestionSimple and best practice solution for x^22xyy^21=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework